Activity part 2: int [ {1 / 2sec(theta)} * {2sec^2(theta)} ] d-theta = 2 LN|sec(theta)+tan(theta)| + C

[armn91]

This is the second part of the activity...

 

[khansaheb]

This is the second part of the activity...

As it was pointed out in the first part:

Activity part 1: int [ 2 / sqrt{x^2 + 6x + 5} ] dx = 2 int [ 1 / sqrt{(x+3)^2 - 4} ] dx = ?

Hello, could you please let me know if what I am doing is correct ? There are two pictures, I will upload the second one in another thread. Thank you!!

www.freemathhelp.com

You have started with incorrect "result" of first part.