renegade05 Full Member Joined Sep 10, 2010 Messages 260 Jul 20, 2011 #1 [attachment=066pmli4]Capture.JPG[/attachment66pmli4] Alright, I know this is probably super easy, but how do you do this? I am stuck. And yes of course this is on a no-calculator portion of an exam - and I am guessing there is a series i need to evaluate. Attachments Capture.JPG 17 KB · Views: 22
[attachment=066pmli4]Capture.JPG[/attachment66pmli4] Alright, I know this is probably super easy, but how do you do this? I am stuck. And yes of course this is on a no-calculator portion of an exam - and I am guessing there is a series i need to evaluate.
G galactus Super Moderator Staff member Joined Sep 28, 2005 Messages 7,203 Jul 20, 2011 #2 I presume this is a practice exam?. Break up each term: \(\displaystyle \left(\underbrace{1-\frac{1}{2}}_{\text{1/2}}\right)+\left(\underbrace{\frac{1}{2}-\frac{1}{3}}_{\text{1/6}}\right)+\left(\underbrace{\frac{1}{3}-\frac{1}{4}}_{\text{1/12}}\right)+\cdot\cdot\cdot +\left(\frac{1}{k-1}-\frac{1}{k}\right)+\left(\frac{1}{k}-\frac{1}{k+1}\right)\) See?. It telescopes.
I presume this is a practice exam?. Break up each term: \(\displaystyle \left(\underbrace{1-\frac{1}{2}}_{\text{1/2}}\right)+\left(\underbrace{\frac{1}{2}-\frac{1}{3}}_{\text{1/6}}\right)+\left(\underbrace{\frac{1}{3}-\frac{1}{4}}_{\text{1/12}}\right)+\cdot\cdot\cdot +\left(\frac{1}{k-1}-\frac{1}{k}\right)+\left(\frac{1}{k}-\frac{1}{k+1}\right)\) See?. It telescopes.