Find four consecutive odd integers such that twice the second, added to the last, is 25.
S shortnsporty New member Joined Sep 16, 2010 Messages 3 Sep 16, 2010 #1 Find four consecutive odd integers such that twice the second, added to the last, is 25.
D Deleted member 4993 Guest Sep 16, 2010 #2 shortnsporty said: Find four consecutive odd integers such that twice the second, added to the last, is 25. Click to expand... Start with defining consecutive odd integers as: (2n-3), (2n -1), (2n+1) and (2n+3) Now twice the second, added to the last, is 25 turns into: 2 * (2n-1) + (2n +3 ) = 25 solve for 'n' from above and then solve for the numbers.
shortnsporty said: Find four consecutive odd integers such that twice the second, added to the last, is 25. Click to expand... Start with defining consecutive odd integers as: (2n-3), (2n -1), (2n+1) and (2n+3) Now twice the second, added to the last, is 25 turns into: 2 * (2n-1) + (2n +3 ) = 25 solve for 'n' from above and then solve for the numbers.
