hello. SO i'm having trouble with this question that's coming up on my test tomorrow and I have no means of contacting my teacher, so I need help please. Its this: Exactly seventy five percent of the members of a club fill exactly 5/6 of the chairs in the room. The smallest possible number of people in the club is? I have no means of solving and don't understand anything except that i know that Diophantine equations are written in the form ax+by=c. my info might be incorrect. pls help, much appreciated
Who are you? You aren't the OP; are you someone else who was given the same problem? Where does it come from? (Were you actually told that this very problem would be on your test?)
It may be worth knowing that
you don't need to know anything about Diophantine equations to solve this.
You're wrong in what you say about them, which applies only to
linear equations; the defining property of Diophantine equations is merely that they require
integer solutions. So my guess is that both of you haven't really learned anything about that, and the problem probably does not assume you have.
On the other hand, it would be very helpful to us if we knew something about your context, such as what level you are at in school, and what you are learning. Is this for an algebra class, or something else? It's possible to solve this even if you haven't learned any but the most basic algebra.
Exactly seventy five percent of the members of a club fill exactly 5/6 of the chairs in the room. What is the smallest possible number of people in the club?
If either of you had answered the direct questions that were asked, then you would have written an equation (or something else) we could talk about! Things would go so much quicker if people would cooperate ...
I'll write the equation: 3/4 M = 5/6 C. Do you see why?
Do you see that since both sides represent the number of chairs sat in, they must be a whole number? What must M be divisible by? What must C be divisible by? You could simply try numbers, starting at the smallest, to find a pair that work.
Or, using a little more thought, you could try solving for either M or C in terms of the other, and see what more that tells you about divisibility, reducing the number of things to try.
Basically, you just have to be willing to
start trying things. Show us
any sort of thought, and we can probably give you a little nudge in the direction of a solution. Our goal is to help you use whatever you know, and so far, we know nothing about that, which is why we can't do much for you yet.