Don't worry: you wrote it properly using grouping symbols. I wanted to check because many students when they first come here are a bit sketchy about grouping symbols.
OK Here is the GENERAL method to SIMPLIFY algebraic fractions.
In this problem you have a denominator that is partly a fraction and partly not a fraction. If you have such a beast in either numerator or denominator or both, turn both the numerator and denominator into pure fractions as a FIRST step. In the case of your problem, you have this mixed form in the denominator so you need to turn both numerator and denominator into pure fractions.
What is the denominator in pure fractional form?
What is the numerator in pure fractional form?
The SECOND step is to turn the division into multiplication through the following identity \(\displaystyle \dfrac{\frac{a}{b}}{\frac{c}{d}} = \dfrac{a}{b} * \dfrac{d}{c}\). In other words you turn one complicated fraction into the product of two simpler fractions.
What two fractions to multiply together do you end up with from the fraction resulting from step 1?
The THIRD step is to cancel any FACTORS that appear in both a numerator and a denominator. In this case, you do not have any such factors so you can ignore this step, but it is an important part of the general method.
The FOURTH step is to do whatever multiplications are necessary to form a single fraction.
Your problem has now been SIMPLIFIED to the form \(\displaystyle \dfrac{e}{f} = 4\).
What do you do next?
