Algebra I problem

[blackshadow_74]

The question is "the length was the rectangle was 2x the width. if you subtracted 3 from the width and added 4 to the length and the area of those 2 nunbers equaled 600m², what was the original length and width of the rectangle?" Can you please show the steps too?

 

[lookagain]

The question is "the length was the rectangle was 2x the width. if you subtracted 3 from the width and added 4 to the length and the area of those 2 nunbers equaled 600m², what was the original length and width of the rectangle?" Can you please show the steps too?

Try something closer to this version:

"The length of the rectangle was twice the width. If you subtracted three meters
from the width and added four meters to the length, the area of the new rectangle
equaled 600 square meters. What were the length and width of the original
rectangle?"

Maybe let w = the number of meters of the width of the original rectangle.
Then 2w = the number of meters of the length of the original rectangle.

Start from there and write down on paper and on the screen more steps
from there.

 

[Steven G]

Sorry but this being a math help forum and not a homework service site no one where will solve your problem for you, let alone supply you with steps.

We prefer to help you solve your problem by giving you leading hints.

 

[HallsofIvy]

The question is "the length was the rectangle was 2x the width. if you subtracted 3 from the width and added 4 to the length and the area of those 2 nunbers equaled 600m², what was the original length and width of the rectangle?" Can you please show the steps too?

Call the length x and the width y.
"the length was the rectangle was 2x the width." so x= 2y.
"if you subtracted 3 from the width"
The new width would be y- 3
"and added 4 to the length"
The new length is x+ 4.
"the area of those 2 numbers equaled 600m²"
Strictly speaking number do NOT have "area"! I suspect they mean the product of those 2 numbers or the area of the rectangle having the new width and length.
(y- 3)(x+ 4)= 600.

You are to solve the two equations x= 2y and (y- 3)(x+ 4)= 600.

 

[HenryTorres]

That is what i was searching for and here i found this.