C callmelexis New member Joined Feb 16, 2010 Messages 1 Feb 16, 2010 #1 ok, the question asks. [attachment=0:3uvaxz4x]help.png[/attachment:3uvaxz4x] ^^^thats what the problem looks like, if my explaining is overrated Attachments help.png 11.1 KB · Views: 44
ok, the question asks. [attachment=0:3uvaxz4x]help.png[/attachment:3uvaxz4x] ^^^thats what the problem looks like, if my explaining is overrated
S soroban Elite Member Joined Jan 28, 2005 Messages 5,584 Feb 16, 2010 #2 Hello, callmelexis! \(\displaystyle \text{Describe how the function has been transformed from: }\,y \,=\,\frac{1}{x}\) . . . \(\displaystyle y \:=\:\frac{-6x-22}{x+4}\) Click to expand... \(\displaystyle \text{Dividing, we have: }\:y \;=\;\frac{2}{x+4} - 6\) \(\displaystyle \text{We know the graph of }\,y_1 \:=\:\frac{1}{x}\) \(\displaystyle \text{The graph of }\:y_2 \:=\:\frac{1}{x+4}\:\text{ is }y_1\text{ moved 4 units to the left.}\) \(\displaystyle \text{The graph of }\:y_3 \:=\:\frac{2}{x+4}\:\text{ is }y_2\text{ dilated by a factor of 2.}\) \(\displaystyle \text{The graph of }\:y \:=\:\frac{2}{x+4}-6\:\text{ is }y_3\text{ lowered 6 units.}\)
Hello, callmelexis! \(\displaystyle \text{Describe how the function has been transformed from: }\,y \,=\,\frac{1}{x}\) . . . \(\displaystyle y \:=\:\frac{-6x-22}{x+4}\) Click to expand... \(\displaystyle \text{Dividing, we have: }\:y \;=\;\frac{2}{x+4} - 6\) \(\displaystyle \text{We know the graph of }\,y_1 \:=\:\frac{1}{x}\) \(\displaystyle \text{The graph of }\:y_2 \:=\:\frac{1}{x+4}\:\text{ is }y_1\text{ moved 4 units to the left.}\) \(\displaystyle \text{The graph of }\:y_3 \:=\:\frac{2}{x+4}\:\text{ is }y_2\text{ dilated by a factor of 2.}\) \(\displaystyle \text{The graph of }\:y \:=\:\frac{2}{x+4}-6\:\text{ is }y_3\text{ lowered 6 units.}\)
