Translate the equation then solve.
The difference of a number and six is subtracted from the difference of twice the number and seven so that the result is two.
A. (2x-7)-(x-6)=2
B. (x-6)-(2x-7)=2
C. (x-6)-(7-2x)=2
D. (7-2x)-(6-x)=2
First of all I think the equation is letter B.
(x-6)-(2x-7)=2
x-6-2x+7=2 <-- Distribute the -1
-x+1=2 <-- Simplifying
-1 -1 <-- bringing like terms to the same side
-x=1
-- --
-1 -1
x=-1
Where did I go wrong? -1 is NOT the answer...
The difference of a number and six is subtracted from the difference of twice the number and seven so that the result is two.
A. (2x-7)-(x-6)=2
B. (x-6)-(2x-7)=2
C. (x-6)-(7-2x)=2
D. (7-2x)-(6-x)=2
First of all I think the equation is letter B.
(x-6)-(2x-7)=2
x-6-2x+7=2 <-- Distribute the -1
-x+1=2 <-- Simplifying
-1 -1 <-- bringing like terms to the same side
-x=1
-- --
-1 -1
x=-1
Where did I go wrong? -1 is NOT the answer...