Algebra word problem

Kimbersqk

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Feb 4, 2012
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8
Translate the equation then solve.

The difference of a number and six is subtracted from the difference of twice the number and seven so that the result is two.

A. (2x-7)-(x-6)=2
B. (x-6)-(2x-7)=2
C. (x-6)-(7-2x)=2
D. (7-2x)-(6-x)=2


First of all I think the equation is letter B.

(x-6)-(2x-7)=2
x-6-2x+7=2 <-- Distribute the -1
-x+1=2 <-- Simplifying
-1 -1 <-- bringing like terms to the same side
-x=1
-- --
-1 -1

x=-1

Where did I go wrong? -1 is NOT the answer...
 
Translate the equation then solve.

The difference of a number and six is subtracted from the difference of twice the number and seven so that the result is two.

A. (2x-7)-(x-6)=2
B. (x-6)-(2x-7)=2
C. (x-6)-(7-2x)=2
D. (7-2x)-(6-x)=2


First of all I think the equation is letter B.

(x-6)-(2x-7)=2
x-6-2x+7=2 <-- Distribute the -1
-x+1=2 <-- Simplifying
-1 -1 <-- bringing like terms to the same side
-x=1
-- --
-1 -1

x=-1

Where did I go wrong? -1 is NOT the answer...

That is because you chose the wrong equation.

The difference of a number and six is subtracted from the difference of twice the number and seven so that the result is two.

If 5 is subtracted from 7, we write that as 7 - 5

If x is subtracted from y, we write that as y - x

In view of the above, which equation you should have chosen?
 
That is because you chose the wrong equation.

The difference of a number and six is subtracted from the difference of twice the number and seven so that the result is two.

If 5 is subtracted from 7, we write that as 7 - 5

If x is subtracted from y, we write that as y - x

In view of the above, which equation you should have chosen?

I believe it is (2x-7)-(x-6)=2
2x-7-x+6=2
x-1=2
+1 +1
x=3
 
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