100 + (0.1 * D) = 3600 - 1000 - [0.426 * (10,000 - D)]

- Thread starter Fogel
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100 + (0.1 * D) = 3600 - 1000 - [0.426 * (10,000 - D)]

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- Jan 27, 2012

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The problem is to solve the equation

100+ 0.1D= 3600- 1000- [0.463(10000- D)]

The first thing I would do is "clean up" the right side of the equation:

3600- 1000= 2600 and 0.436(10000- D)= 4360- 0.463D so

100+ 0.1D= 2600- 4360+ 0.436D= -1760+ 0.436D.

To solve 100+ 0.1D= -1760+ 0.436D, first add 1760 to both sides to get 1860+ 0.1D= 0.436D. Now subtract 0.1D from both sides to get 1860= 0.336D. Finally, divide both sides by 0.336:

D= 1860/0.336= 5535.71428571428571428571428571425....