Algebraic quandry

Fogel

New member
Joined
Apr 23, 2019
Messages
4
Hello, I've been given the following equation to solve. I've even been told the answer - as being 5400 - but I am not sure how one would go about solving for the variable "D", which is on both sides of the equation, and this variable seems "difficult to get at". Thank you in advance for any possible advice.
100 + (0.1 * D) = 3600 - 1000 - [0.426 * (10,000 - D)]
 

Jomo

Elite Member
Joined
Dec 30, 2014
Messages
4,893
Can we please see your work so we can guide you to the correct answer? Thanks
 

Fogel

New member
Joined
Apr 23, 2019
Messages
4
Hi Jomo, I just ran into a similar problem and it showed me the step that was needed, which I was overlooking before. So the case is solved. Many thanks.
 

HallsofIvy

Elite Member
Joined
Jan 27, 2012
Messages
5,449
For any who are still wondering:
The problem is to solve the equation
100+ 0.1D= 3600- 1000- [0.463(10000- D)]

The first thing I would do is "clean up" the right side of the equation:
3600- 1000= 2600 and 0.436(10000- D)= 4360- 0.463D so
100+ 0.1D= 2600- 4360+ 0.436D= -1760+ 0.436D.

To solve 100+ 0.1D= -1760+ 0.436D, first add 1760 to both sides to get 1860+ 0.1D= 0.436D. Now subtract 0.1D from both sides to get 1860= 0.336D. Finally, divide both sides by 0.336:
D= 1860/0.336= 5535.71428571428571428571428571425....
 
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