An artist takes a piece of wire that measures 4 ft 8 in and bent it to design a square.

[eddy2017]

Hi, i am having a little bit of trouble find a missing step in this problem.

an artist takes a piece of wire that measures 4 by 8 and bent it to design a square. find the total area of the square.
I know the area of a square is found using this formula
A=s^2 ( s= side)

but aren't the sides of a square supposed to be equal in length? why 4 by 8, or is it a flawed problem?

thanks,
eddy

 

[BigBeachBanana]

Hi, i am having a little bit of trouble find a missing step in this problem.

an artist takes a piece of wire that measures 4 by 8 and bent it to design a square. find the total area of the square.
I know the area of a square is found using this formula
A=s^2 ( s= side)

but aren't the sides of a square supposed to be equal in length? why 4 by 8, or is it a flawed problem?

thanks,
eddy

A piece of wire is one-dimensional. How can you measure a wire 4x8?

 

[eddy2017]

A piece of wire is one-dimensional. How can you measure a wire 4x8?

The only thing that comes to mind is straightening it. That is the only way it can be measured.

 

[lev888]

Hi, i am having a little bit of trouble find a missing step in this problem.

an artist takes a piece of wire that measures 4 by 8 and bent it to design a square. find the total area of the square.
I know the area of a square is found using this formula
A=s^2 ( s= side)

but aren't the sides of a square supposed to be equal in length? why 4 by 8, or is it a flawed problem?

thanks,
eddy

From 4 by 8 you need to figure out the side of the square. But I also don't understand what those numbers mean.

 

[eddy2017]

So there is a flaw in the problem. I'm gonna discard it.

 

[eddy2017]

Oh I think I made a mistake.
It is like this:

A piece of wire measuring 4ft 8in long is bent by an artist to make a square. what is the area?​

 

[eddy2017]

So I believe that the square having four equal sides I will have to divide 4ft 8 in by 4. Right?

 

[Deleted member 4993]

So I believe that the square having four equal sides I will have to divide 4ft 8 in by 4. Right?

Yes - that would be one side of the square!.

 

[eddy2017]

4.8 ÷ 4= 1 ft 2 in.
I'll take this to inches= 14 in
So, I can apply the formula to find the area of a square.
A= s^2
A=14^2
A=196 in^2
What's the great FIND?
The area of the square is 196 squared inches.

 

[BigBeachBanana]

4.8 ÷ 4= 1 ft 2 in.
I'll take this to inches= 14 in
So, I can apply the formula to find the area of a square.
A= s^2
A=14^2
A=196 in^2
What's the great FIND?
The area of the square is 196 squared inches.

[math]\text{4ft 8inches}\neq \text{4.8 ft}[/math]

 

[eddy2017]

[math]\text{4ft 8inches}\neq \text{4.8 ft}[/math]

4 ft 8 inches taken to inches is
1ft = 12 inches
12*4 =48 in + 8 in =56 in
56 in ÷ 4 (sides)= 14
A= 14^2
A=196 inches

 

[lookagain]

1ft = 12 inches
12*4 =48 in + 8 in =56 in \(\displaystyle \ \ \ \ \ \ \)missing unit, incorrect use of train of equalities
56 in ÷ 4 (sides)= 14 \(\displaystyle \ \ \ \ \ \ \ \ \ \ \ \)missing unit
A= 14^2\(\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \)missing unit
A=196 inches \(\displaystyle \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \)wrong type of unit

Here are corrections:

(12 in.)*4 = 48 in.
48 in. + 8 in. = 56 in.
(56 in.)/4 = 14 in.
A = (14 in.)^2
A = 196 sq. in.

 

[eddy2017]

Here are corrections:

(12 in.)*4 = 48 in.
48 in. + 8 in. = 56 in.
(56 in.)/4 = 14 in.
A = (14 in.)^2
A = 196 sq. in.

Thanks, lookagain. Valid point. Good to hear from you.