evenkeel3x
New member
- Joined
- Feb 28, 2010
- Messages
- 14
Hello, I need help doing this identity:
(1+cosX)(tanX/2)=sinX
No obvious formulas come to mind, but I've tried to manipulate the tan double angle formula to accomodate X/2.
This is the origional tan double angle formula:
tan(2X)=(2tanX)/(1-tan^2X)
I then tried to divide the right side by four to hopefully equal the tanX/2 value. I don't even know if that's legal.
So now I have:
(1+cosX) ((2tanX)/(1-tan^2X))/4=sinX
And now I'm very wholeheartedly stuck. It's probably something simple I'm missing, but I don't know.
A Quick Response would be greatly appreciated!
Thanks.
(1+cosX)(tanX/2)=sinX
No obvious formulas come to mind, but I've tried to manipulate the tan double angle formula to accomodate X/2.
This is the origional tan double angle formula:
tan(2X)=(2tanX)/(1-tan^2X)
I then tried to divide the right side by four to hopefully equal the tanX/2 value. I don't even know if that's legal.
So now I have:
(1+cosX) ((2tanX)/(1-tan^2X))/4=sinX
And now I'm very wholeheartedly stuck. It's probably something simple I'm missing, but I don't know.
A Quick Response would be greatly appreciated!
Thanks.