angles formed by parallel lines and transversals

[1yoyo105]

I'm stumped at (3x-45)°=(2x+15)° What do I do? I have a couple more of these so if some one could explain this, things would go so much easier for me.

 

[Denis]

Post the problem IN FULL.
If something is squared, use ^2; like 4^2 = 16

 

[mmm4444bot]

(3x - 45)°= (2x + 15)° What do I do?

I had to use my browser's zoom function, to discover that those two specks are degree symbols. ("It's **** getting old.")

So, I would guess that you're trying to find the value of x that makes the measure of both angles equal.

If so, you need to solve this linear equation:

3x - 45 = 2x + 15

Combine the terms that contain a factor of x (those are called like-terms because they each contain x). The combined x-term will be on one side of the equation.

Combine the constants on the opposite side of the equation (constants are also known as like-terms).

Here are the steps to do it:

(1) Subtract 2x from both sides

(2) Add 45 to both sides

If you need to study some lessons on solving linear equations, click HERE.

If there is more to your exercise than finding the solution for x, then you better follow Denis' first instruction.