#### needhelpmom

##### New member

- Joined
- Oct 5, 2005

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(round to the nearest 100th of an hour)

- Thread starter needhelpmom
- Start date

- Joined
- Oct 5, 2005

- Messages
- 5

(round to the nearest 100th of an hour)

Let the time they finish work = t.

Hours worked = (t - start time).

Wage = hours worked * hourly rate.

Wage = (t-start time)*hourly rate

They earn the same

(t-8)*6.75 = (t-10)*8.9

6.75t - 54 = 8.9t - 89

35 = 2.15t

3500/215 = t

700/43 = t

The hours the bagger worked = 700/43 - 8.

The hours worked by the cashier = 700/43 - 10.

Multiply these by there respective hour rate to check they did earn the same.

Perhaps you can wrestle with this until someone posts a simpler way.

- Joined
- Oct 5, 2005

- Messages
- 5

any suggestions for me.

Hard to give "suggestions", but maybe if you look at this way of doing it,needhelpmom said:

it may help you:

Let h = hours by cashier earning $6.75 per hour;

then hours by other cashier = h - 2 : follow that, mom?

so $6.75 cashier earned: 6.75 * h,

and other cashier earned: 8.90 * (h - 2);

still with me?

And, since what they earned is the SAME, then:

8.90(h - 2) = 6.75(h)

8.90(h) - 17.80 = 6.75(h)

8.90(h) - 6.75(h) = 17.80

2.15(h) = 17.80

h = 17.80 / 2.15 = 8.279...

So they worked 8.28 and 6.28 hours.

Don't be shy if you have questions on above.