So I'm going to try to work this problem now so you can see my faulty.partially correct thinking in action:
The cost of an anorak rose by £6. As a result a shop could buy five fewer anoraks for £600. If the cost of the anorak was £x before the rise, find expressions, in terms of x, for the number of anoraks which could be bought before and after the rise. Hence form an equation in x and show that it reduces to x^2 + 6x -720 =0. Solve this equation and state the original cost of the anorak.
So the number of anoraks before the rise will be 600/x and after: (600/x) - 5. So to make an equation out of that:
(600/x) -5 = 600/(x+6) then (600/x) - 600/(x+6) -5 = 0 . So now I'm thinking I need to create common denominator:
(600(x-6))/(x^2+6x) - 600x/(x^2+6x) -5 =0
(600x -3600)/(x^2 +6x) - 600x/(x^2+6x) -5 =0
(-3600/(x^2+6x)) - 5 =0
got a bit lost-if anyone can give me a nudge (throw a life belt!) that would be great-thanks
The cost of an anorak rose by £6. As a result a shop could buy five fewer anoraks for £600. If the cost of the anorak was £x before the rise, find expressions, in terms of x, for the number of anoraks which could be bought before and after the rise. Hence form an equation in x and show that it reduces to x^2 + 6x -720 =0. Solve this equation and state the original cost of the anorak.
So the number of anoraks before the rise will be 600/x and after: (600/x) - 5. So to make an equation out of that:
(600/x) -5 = 600/(x+6) then (600/x) - 600/(x+6) -5 = 0 . So now I'm thinking I need to create common denominator:
(600(x-6))/(x^2+6x) - 600x/(x^2+6x) -5 =0
(600x -3600)/(x^2 +6x) - 600x/(x^2+6x) -5 =0
(-3600/(x^2+6x)) - 5 =0
got a bit lost-if anyone can give me a nudge (throw a life belt!) that would be great-thanks