V Valentas New member Joined Dec 19, 2010 Messages 34 May 10, 2011 #1 It is given f(x) = 2cos(2x - pi/3) The question is: I need to find out coordinates where crosses this graph with another straight: a) x = 9pi/2 b) y = -1 Really need help.
It is given f(x) = 2cos(2x - pi/3) The question is: I need to find out coordinates where crosses this graph with another straight: a) x = 9pi/2 b) y = -1 Really need help.
D Deleted member 4993 Guest May 10, 2011 #2 Valentas said: It is given f(x) = 2cos(2x - pi/3) The question is: I need to find out coordinates where crosses this graph with another straight: a) x = 9pi/2 Need to evaluate f(9?/2) b) y = -1 -1 = 2*cos(2*x - ?/3) solve for 'x' Really need help. Click to expand...
Valentas said: It is given f(x) = 2cos(2x - pi/3) The question is: I need to find out coordinates where crosses this graph with another straight: a) x = 9pi/2 Need to evaluate f(9?/2) b) y = -1 -1 = 2*cos(2*x - ?/3) solve for 'x' Really need help. Click to expand...
V Valentas New member Joined Dec 19, 2010 Messages 34 May 10, 2011 #3 Need to evaluate f(9?/2) Still can't get the point why should I do that...
D Deleted member 4993 Guest May 10, 2011 #4 "x = a" is a vertical line. It will intersect f(x) at [a,f(a)]