#### durgethedemonhunter

##### New member

- Joined
- Dec 10, 2004

- Messages
- 2

[-6 , (6/ {3})] i know the first part of the formula r={x^2 + y^2} but ive found conflicting info on the second part which i belive to be either

rtan (y/x) or r tan^-1 (y/x) now ive work out the first part and im preety sure its this

r = {(-6)^2 + (6/{3})^2} => r = {36 + 12} => r = {48} => r = 2{3}

that works out into radians at either 2Pi/3 & csc 120 or 5Pi/6 & sec 150

the book im useing in my class suks and only touchs breifly on this so any help woul be awsome