I am having trouble figuring out how to complete this problem. I am trying to find the point(s) at which the function is continuous.
y = ∜3x-1
(y = 4th root of 3x - 1)
So far this is what I have:
3x - 1 < 0
3x < 1
x < 1/3, so the function is continuous at x ≥ 1/3. Is this correct, or am I completely missing the idea? Thanks!
y = ∜3x-1
(y = 4th root of 3x - 1)
So far this is what I have:
3x - 1 < 0
3x < 1
x < 1/3, so the function is continuous at x ≥ 1/3. Is this correct, or am I completely missing the idea? Thanks!