I am unsure of this question. I used a calculator to work out the p (X=5) using a Poisson distribution. X~Po(2), and the p value is 0.036, based on this i would think that the H0 is rejected at 5% probability. I have changed it to 'accepted' so the cross was actually for rejected.
I am very sorry i have the answer to this now. its the cumulative probability of x>=5 that we need. ie the entire tail when x >=5. the only way to work this out is P(x>=5)= 1-P(x=<4)=0.0527
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