Let R be the region in the fourth quadrant enclosed by the x-axis and the curve y=x²-2kx, where k is a constant. If the area of the region R is 36, then the value of k is
a)-3
b)3
c)4
d) 6
I know that in order to solve this problem, area under the curve is found by using an intergral under which case we would need to know the bottom and top x values. The bottom value would be 0 because it is only in the fourth quadrant whose area is being measured. We know that the total area is 36 but I dont know how to attain the top value (b) in order to then obtain the value of k.
b
∫ (x²-2kx) dx = 36
a
The answer is supposed to be B. But I still dont know how to get to the answer.
a)-3
b)3
c)4
d) 6
I know that in order to solve this problem, area under the curve is found by using an intergral under which case we would need to know the bottom and top x values. The bottom value would be 0 because it is only in the fourth quadrant whose area is being measured. We know that the total area is 36 but I dont know how to attain the top value (b) in order to then obtain the value of k.
b
∫ (x²-2kx) dx = 36
a
The answer is supposed to be B. But I still dont know how to get to the answer.