ms.cupcake
New member
- Joined
- Mar 27, 2013
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- 8
6^3 x 6^4 x 6^5 x....6^(p-1) x 6^p = (1/6)^-900. what is p? help me please. im stuck since (1/6)^-900 is at infinity. thanks for advance.
Note that: .\(\displaystyle \left(\tfrac{1}{6}\right)^{-900} \:=\:\left(6^{-1}\right)^{-900} \:=\:6^{900}\)Solve for \(\displaystyle p:\;6^3\cdot6^4\cdot6^5\:\cdots\,6^p \:=\: \left(\tfrac{1}{6}\right)^{-900}\)
I'm stuck since (1/6)^-900 is at infinity. .What does that mean?
Your statement that "(1/6)^-900 is at infinity" suggests that you think the left side is an infinite product. That is not the case- has exactly p- 2 terms in it.6^3 x 6^4 x 6^5 x....6^(p-1) x 6^p = (1/6)^-900. what is p? help me please. im stuck since (1/6)^-900 is at infinity. thanks for advance.