#### FriendlyAsian

##### New member

- Joined
- Mar 22, 2019

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- 16

^{3}+ y and y

^{3}+ x are divisible by x

^{2}+ y

^{2}

- Thread starter FriendlyAsian
- Start date

- Joined
- Mar 22, 2019

- Messages
- 16

- Joined
- Mar 22, 2019

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How can I do the divisions?

- Joined
- Mar 22, 2019

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- 16

I mean, I tried to do the divisons but I still can not solve it.

- Joined
- Mar 22, 2019

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Thanks

- Joined
- Mar 22, 2019

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- Joined
- Mar 22, 2019

- Messages
- 16

Since both xy

(x + y)(x

=> (x+ y)(xy - 1) is divisible by x

Let x + y be a, xy be b (a, b are positive integers)

=> a(b - 1) is divisible by a

=>a

We also have a

=>a - 2b

Because a and b are positive integers so that 2b

=>a

=>a - 2b

=>2b

=>b = 1

=>xy = 1

=>x=y=1