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JASON RULES

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Hi. Sorry if this is against a rule. I had a tutor who changed his mind 7 times on one problem. I completed this assignment but I just want to make sure that everything is correct before submitting it. Thanks!




4. Write in exponential form: log x = y

A: 10 to the y power = x

10. Solve for x exactly: log base x 25 = 2

A: x = 5

12. Solve for x to three significant digits: 10 to the x power = 17.5

A: x = 1.243

14. (Same directions as 12) ln x = -0.01573

A: x = 0.984

26. Solve for x exactly: 4 - (3 to the x power) = 2

A: x = 0.631

30. Same as 26: log base x 9 = -2

A: x = 0.333

46. Same as 26: log x - log 3 = log 4 - log (x + 4)

A: x = 2

50. Still the same ****: ln (log Dead = 1

A: x= 522.735

60. Solve for I: D = 10 log (I / I o)

A: I = Io (10 to the D / 10 power)

62. Solve for I: x = -1/k (ln) I/Io

A: I = Io(e to the -kx power)

70. How long will it take the population to double? Use this formula (P=Poe to the rt power)

r = 3%

A: t= 21.105 years

72. (ugh..)

One leukemic cell injected into a healthy mouse will divide into two cells in about half a day. At the end of the day these cells will divide into four. This doubling continues until 1 billion cells are formed; then the animal dies with leukemic cells in every part of the body

Part A: Write an equation that will give the Number N of leukemic cells at the end of t days

Part B: When, to the nearest day, will the mouse die?

Answers:

A: t = 9 / 2 log 2

B: 15 days

76. 8.3 = (2 / 3) log (E/Eo) , Solve for E where Eo = 10 to the 4.4 joules

A: E = 10 to the 16.85 power


Thanks!
 
JASON RULES said:
Hi. Sorry if this is against a rule. I had a tutor who changed his mind 7 times on one problem. I completed this assignment but I just want to make sure that everything is correct before submitting it. Thanks!




4. Write in exponential form: log x = y

A: 10 to the y power = x <<< Correct x = 10[sup:284h6jxo]y[/sup:284h6jxo]
10. Solve for x exactly: log base x 25 = 2

A: x = 5<<< Correct

12. Solve for x to three significant digits: 10 to the x power = 17.5

A: x = 1.243<<< Correct

14. (Same directions as 12) ln x = -0.01573

A: x = 0.984<<< Correct

26. Solve for x exactly: 4 - (3 to the x power) = 2

A: x = 0.631<<< Correct

30. Same as 26: log base x 9 = -2

A: x = 0.333<<< Correct

46. Same as 26: log x - log 3 = log 4 - log (x + 4)

A: x = 2<<< Correct

50. Still the same ****: ln (log Dead = 1

A: x= 522.735

60. Solve for I: D = 10 log (I / I o)

A: I = Io (10 to the D / 10 power)<<< Correct I = I[sub:284h6jxo]o[/sub:284h6jxo]10[sup:284h6jxo]D/10[/sup:284h6jxo]

62. Solve for I: x = -1/k (ln) I/Io

A: I = Io(e to the -kx power)<<< Correct I = I[sub:284h6jxo]o[/sub:284h6jxo]e [sup:284h6jxo]-kx[/sup:284h6jxo]

70. How long will it take the population to double? Use this formula (P=Poe to the rt power)

r = 3%

A: t= 21.105 years<<< Correct - but how do you know it is years - where in the problem does it say that 't' is measured in years

72. (ugh..)

One leukemic cell injected into a healthy mouse will divide into two cells in about half a day. At the end of the day these cells will divide into four. This doubling continues until 1 billion cells are formed; then the animal dies with leukemic cells in every part of the body

Part A: Write an equation that will give the Number N of leukemic cells at the end of t days

Part B: When, to the nearest day, will the mouse die?

Answers:

A: t = 9 / 2 log 2 <<< Incorrect - it should be a function like N = N[sub:284h6jxo]o[/sub:284h6jxo]2[sup:284h6jxo]2t[/sup:284h6jxo]

B: 15 days<<< Correct

76. 8.3 = (2 / 3) log (E/Eo) , Solve for E where Eo = 10 to the 4.4 joules

A: E = 10 to the 16.85 power<<< Correct


Thanks!
 
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