Avogadro's number

  • Thread starter Deleted member 4993
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If there were 24 identical balls in a bowl - marked 1 through 24 - and

somebody picked one ball at a time - without replacement - 24 times

the probability of picking the balls 1,2,3,4,5 ..... 21,22,23,24 in consecutive order is ~ 1 in Avogadro's number. (i.e. 24! ~ 6 * 1023)
 
If there were 24 identical balls in a bowl - marked 1 through 24 - and

somebody picked one ball at a time - without replacement - 24 times

the probability of picking the balls 1,2,3,4,5 ..... 21,22,23,24 in consecutive order is ~ 1 in Avogadro's number. (i.e. 24! ~ 6 * 1023)
Within about 3% which is pretty darn good for a guestimate.
 
If there were 24 identical balls in a bowl - marked 1 through 24 - and
somebody picked one ball at a time - without replacement - 24 times
the probability Avogadro's number. (i.e. 24! ~ 6 * 1023)
Avogadro's number is about 6.022141×10^23

24!=

I just don't understand your point. Can you heep mr?
 
Within about 3% which is pretty darn good for a guestimate.

Actually:

24! = 6.2044840173323943936 × 10^23Avogadro's number = 6.022141×10^23

error = (6.2044840173323943936 × 10^23 - 6.022141×10^23)/6.2044840173323943936 × 10^23 * 100% = 2.9388%:p:p:p
 
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