Hello,
I have found this method to find the soulution of differential equation which is:
yn=(2/3)hf(xn,yn)+(4/3)yn-1-(1/3)yn-2;
where y'(x)= f(x,y(x))
and h is the step size.
the question now how can I find f(xn,yn) if it depend on the value os yn?
Regards
I have found this method to find the soulution of differential equation which is:
yn=(2/3)hf(xn,yn)+(4/3)yn-1-(1/3)yn-2;
where y'(x)= f(x,y(x))
and h is the step size.
the question now how can I find f(xn,yn) if it depend on the value os yn?
Regards