I'm really not sure where I went wrong. I used the chain rule (which isn't covered until a later section...). I tried simplifying, my answer is just not being accepted.
Note: \(\displaystyle \frac{5}{2}5u^{\frac{-1}{2}\) is not correct because
1) the "5u" must have grouping symbols around it,
2) you won't leave the answer with a negative fractional exponent.
The function has the variable inside a radical, so the derivative
should have that variable also inside the radical for consistency in forms.
3) The 5 that would be in the denominator will cancel
out with with the 5 in the numerator of your first fraction,
so you would have just one 5 showing.
4) Also, 25 immediately to the left of 5 does not indicate any multiplication,
that being another reason the grouping symbols would be needed to double
as multiplication. It is meaningless. If you typed it correctly as a possible
intermediate step, it may look like 25(5u)2−1.
One of the last few forms of my solution will be the desired one by your
instructor and/or textbook.
This site uses cookies to help personalise content, tailor your experience and to keep you logged in if you register.
By continuing to use this site, you are consenting to our use of cookies.