Basic fraction problem

[bronx.system]

Hey all i have been trying to work this out for a while and i got the answer but i did it in a weird way
Is there a more a practical way?

A bucket 3/4 full contains 250 mL of water. How much water will the buck contain when 4/5 full.

The way i did it was

3/4 = 75%
to work out what is 100%
0.75 / 250 = 333.333 (not sure what this means but i used it before in other scenarios)

then i worked out what % 4/5 is
4/5 x 100/1 = 400/5
80%

then 80% of 333.333
.80 * 333.333
= 266.666

Is this the best way to do it?

 

[Deleted member 4993]

Hey all i have been trying to work this out for a while and i got the answer but i did it in a weird way
Is there a more a practical way?

A bucket 3/4 full contains 250 mL of water. How much water will the buck contain when 4/5 full.

The way i did it was

3/4 = 75%
to work out what is 100%
0.75 / 250 = 333.333 (not sure what this means but i used it before in other scenarios) This is incorrect. I think you meant 250/0.75

then i worked out what % 4/5 is
4/5 x 100/1 = 400/5
80%

then 80% of 333.333
.80 * 333.333
= 266.666

Is this the best way to do it?

No....

Assume that the volume of the bucket = V

then

A bucket 3/4 full contains 250 mL of water → 3/4 * V = 250 → V = 4/3 * 250

Then

How much water will the buck contain when 4/5 full. Volume water = 4/5 * V = 4/5 * 4/3 * 250 = 800/3 mL= 266.666 mL = 270 mL

 

[bronx.system]

thanks all much appreciated

EDIT: just noticed your quote i read something similar but the original author was unknown to me till now
thanks

"Each new pattern or formula is'nt a new, isolated fact to be memorized, but just a new way of looking at something you already know."