bryanmiller
New member
- Joined
- Jan 23, 2022
- Messages
- 1
A rotating beacon is located 1 miles out in the water. Let A be the point on the shore that is closest to the beacon. As the beacon rotates at 8 rev/min, the beam of light sweeps down the shore once each time it revolves. Assume that the shore is straight.
How fast (in miles/min) is the point where the beam hits the shore moving at an instant when the beam is lighting up a point miles along the shore from the point A?
Hint: consider converting the rotation to radians/min.
Note: Round to the nearest hundredth.
I apologize for my writing. I
have a little issue with writing
1 I took the 8 rev/minute and set to 16pi raidans min-this is dtheta/dt
2. I also figure the hyp of my triangle which is 2 with other sides 1 and sq rt 3-sq rt 3 will also be known as "x"
3 Figured my tan theta which is sq rt of 3/1
4 figured sec^2 d theta/dt
5 so I get 2^2*16pi=sq rt of 3
6 Answer =(64 pi*sq rt of 3)/3
How fast (in miles/min) is the point where the beam hits the shore moving at an instant when the beam is lighting up a point miles along the shore from the point A?
Hint: consider converting the rotation to radians/min.
Note: Round to the nearest hundredth.
I apologize for my writing. I
have a little issue with writing1 I took the 8 rev/minute and set to 16pi raidans min-this is dtheta/dt
2. I also figure the hyp of my triangle which is 2 with other sides 1 and sq rt 3-sq rt 3 will also be known as "x"
3 Figured my tan theta which is sq rt of 3/1
4 figured sec^2 d theta/dt
5 so I get 2^2*16pi=sq rt of 3
6 Answer =(64 pi*sq rt of 3)/3
