• Welcome! The new FreeMathHelp.com forum is live. We've moved from VB4 to Xenforo 2.1 as our underlying software. Hopefully you find the upgrade to be a positive change. Please feel free to reach out as issues arise -- things will be a little different, and minor issues will no doubt crop up.

begining algerba vertex and axis

zouhoer

New member
Joined
Jan 25, 2010
Messages
1
hey, can anyone help me with this problem please.
y=x²-16+63 whats are the vertex and axis of the symmetry of the parabola?
 

mmm4444bot

Super Moderator
Staff member
Joined
Oct 6, 2005
Messages
10,158
Please use the [Preview] button to proofread your posts before clicking [Submit].

I'm guessing that you intended to type the following quadratic equation, instead, but I'm not 100% sure.

y = x^2 - 16x + 63

You can use a formula for calculating the x-coordinate of the vertex.

x = -B/(2A)

Of course, once you know the value of x at the vertex, you can easily calculate the corresponding value of y.

The axis of symmetry for a parabola is simply the vertical line that passes through the vertex.

Can you finish now? Otherwise, if you want more help, please show whatever work you can or explain what you're thinking. :cool:

Cheers ~ Mark
 
Top