S skonk New member Joined Mar 5, 2008 Messages 2 Mar 5, 2008 #1 I need to prove that: (K+1)! + (K+1)(K+1)! -1 = ((K+1) + 1)! - 1 by transforming the left side into the same form as the right. I know that (K+1)! = (K+1) x K! but I'm still getting nowhere. Thanks for the help.
I need to prove that: (K+1)! + (K+1)(K+1)! -1 = ((K+1) + 1)! - 1 by transforming the left side into the same form as the right. I know that (K+1)! = (K+1) x K! but I'm still getting nowhere. Thanks for the help.
skeeter Elite Member Joined Dec 15, 2005 Messages 3,204 Mar 5, 2008 #2 (K+1)! + (K+1)(K+1)! -1 = (K+1)![1 + (K+1)] - 1 = (K+1)!(K+2) - 1 = (K+2)! - 1 = [(K+1) + 1]! - 1
S skonk New member Joined Mar 5, 2008 Messages 2 Mar 6, 2008 #3 Wow! Thanks for the quick response, I see what I was missing
