blending coffee

irene12

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Dec 21, 2010
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I've tried to work this problem out, but I'm stuck. Barstucks is making a new coffee blend. The company bought 50 lbs. of Kona beans at $34.95 per lb. and plans to mix these beans with Columbian beans that sell for $7.99 per lb.wholesale. If Barstucks wants its cost of the blend to be $11.95 per lb. how many lbs. of Colombian beans should it buy? I thought I should find the percentage that could be used to create the 11.95 blend, but nothing is working.
 

Subhotosh Khan

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irene12 said:
I've tried to work this problem out, but I'm stuck. Barstucks is making a new coffee blend. The company bought 50 lbs. of Kona beans at $34.95 per lb. and plans to mix these beans with Columbian beans that sell for $7.99 per lb.wholesale. If Barstucks wants its cost of the blend to be $11.95 per lb. how many lbs. of Colombian beans should it buy? I thought I should find the percentage that could be used to create the 11.95 blend, but nothing is working.
Please show us - how it is not working out.

Please share your work with us - so that we may know where to begin to help you.
 

irene12

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Dec 21, 2010
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50 lbs($34.95) +1 lb(7.99)=x(11.95) Is this on the right track to solving the problem? Irene
 
J

JeffM

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irene12 said:
50 lbs($34.95) +1 lb(7.99)=x(11.95) Is this on the right track to solving the problem? Irene
Short Answer: No.

Road to Long Answer: What is the unknown? The number of pounds of Columbian coffee bought. So write it down. You should have:

x = pounds of Columbian coffee bought.

So how many dollars did Barstucks pay for coffee?

How many pounds of coffee did they get for that money?
 

Denis

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Feb 17, 2004
Messages
1,480
Irene, "showing" it this way will probably make it much easier:

x = required Columbian beans
Code:
50   @ 34.95
 x    @  7.99
============
50+x @ 11.95
 
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