Bring On the Wheel

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mathdad

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How many feet does a wheel with a diameter of x inches travel after y hours?
Note: The answer is not a specific number of feet or inches.

Solution:

C = pi•d

Let d = x

C = pi(x inches)(y hours)

Correct?
 
Is "y" a time in hours or a speed in revolutions per hour? Or both?

A wheel of diameter x inches has a circumference of \(\displaystyle \pi x\) inches so \(\displaystyle \frac{\pi x}{12}\) feet. If it is making y revolutions per hour it will travel \(\displaystyle \frac{\pi xy}{12}\) feet per hour so a total of \(\displaystyle \frac{\pi xy^2}{12}\) feet in y hours.
 
Is "y" a time in hours or a speed in revolutions per hour? Or both?

A wheel of diameter x inches has a circumference of \(\displaystyle \pi x\) inches so \(\displaystyle \frac{\pi x}{12}\) feet. If it is making y revolutions per hour it will travel \(\displaystyle \frac{\pi xy}{12}\) feet per hour so a total of \(\displaystyle \frac{\pi xy^2}{12}\) feet in y hours.

Algebra.com is notorious for having too many incorrect questions posted. I will need to search the site again.
 
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