mathdad
Full Member
- Joined
- Apr 24, 2015
- Messages
- 737
A bus traveling at an average rate of 50 kilometers per hour made the trip to town in 6 hours. If it had traveled at 45 kilometers per hour, how many more minutes would it have taken to make the trip?
Solution:
I need to use D = rt.
I will divide the situation into two cases.
Case 1
rate = 50
time = 6
Distance = 50(6)
Case 2
rate = 45
time = t
Distance = 45t
Distance for Case 1 = Distance for Case 2.
50(6) = 45t
300 = 45t
Solve for t.
300/45 = t
6.6666666667 = t
I am stuck here.
Note: HOW MANY MORE MINUTES, tells me that traveling at 45 k/hr would have taken 6 hours plus additional minutes. How do I find the additional minutes?
Solution:
I need to use D = rt.
I will divide the situation into two cases.
Case 1
rate = 50
time = 6
Distance = 50(6)
Case 2
rate = 45
time = t
Distance = 45t
Distance for Case 1 = Distance for Case 2.
50(6) = 45t
300 = 45t
Solve for t.
300/45 = t
6.6666666667 = t
I am stuck here.
Note: HOW MANY MORE MINUTES, tells me that traveling at 45 k/hr would have taken 6 hours plus additional minutes. How do I find the additional minutes?