L layd33foxx New member Joined Sep 24, 2011 Messages 26 Dec 7, 2011 #1 Calculate f" for f(x)=g(e2x), where g is a function defined for all real numbers & g admits second order derivative.
Calculate f" for f(x)=g(e2x), where g is a function defined for all real numbers & g admits second order derivative.
L layd33foxx New member Joined Sep 24, 2011 Messages 26 Dec 7, 2011 #2 can you check it please. f = g(e^2x) f' = 2e^2x g' f'' = 4e^2xg' + 2e^2xg'' I have expanded out 4e^2xg'(u) + 2e^2xg''(u)
can you check it please. f = g(e^2x) f' = 2e^2x g' f'' = 4e^2xg' + 2e^2xg'' I have expanded out 4e^2xg'(u) + 2e^2xg''(u)
D Deleted member 4993 Guest Dec 7, 2011 #3 layd33foxx said: can you check it please. f = g[e^ (2x) ] f' = 2e^(2x) g' f'' = 4e^(2x)g' + 2e^(2x)g'' I have expanded out 4e^2xg'(u) + 2e^2xg''(u) Click to expand... Looks good - except for those grouping symbols....
layd33foxx said: can you check it please. f = g[e^ (2x) ] f' = 2e^(2x) g' f'' = 4e^(2x)g' + 2e^(2x)g'' I have expanded out 4e^2xg'(u) + 2e^2xg''(u) Click to expand... Looks good - except for those grouping symbols....
