- Thread starter tradewind
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A bit like this? :One line (Line A) has 5 points on it (And so its divided into 4 sections)

The second line (Line B) has 6 points on it (so its divided into 5 sections).

I basically want to compare the two lines and figure out what percentage

the points on Line B fall between when compared to the points on Line A.

For example: Starting at the bottom, Point 1 and Point 2 on Line A have

a distance of .25 (25%) and Point 1 and Point 2 on Line B have a distance

of .2 (20%) so Point 2 on Line B is 80% of the way between

Points 1 and 2 on Line A.

I'm trying to figure out the percentages for the rest of the points on Line B essentially.

So Point 3 (.40%) would fall between Point 2 and 3 on Line A...

so what's the percentage there?

Point 4 (60%) would fall between Point 3 and 4, Point 5 (80%)

would fall between Points 4 and 5, and Point 6 would simply

be 100% when compared to Point 5 of Line A.

A: 1................2...............3...............4................5

B: 1...........2............3.............4............5............6

- Joined
- Jan 5, 2019

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- 18

The line B points will always fall at 80% between the corresponding points on line A.Except point 1, which is 0%, and point 6 which is 100%.

A formula you can use is: [((Pb-1)*20%)/((Pa-1)*25%)]*100

Pb is number of point on line B (e.g. 1,2,3,4,5, or 6)

Pa is corresponding point on line A, so if you choose point 3 on line B then Pa = 3 too.

(Pb-1)*20% and (Pa-1)*25% will give you the exact percentage that each point falls on the line. When you divide first by the second and using the same point number for both equations, you get the fraction that Pb is between Pa and Pa-1. Then *100% to convert the fraction to percentage.

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Yes, So I'm basically trying to get this:A bit like this? :

A: 1................2...............3...............4................5

B: 1...........2............3.............4............5............6

A: 1................2...............3...............4................5

B: 1...........2...|.......3.......|......4........|....5..........6[/QUOTE]

So LineB Point One is 100% to 1 and 0% to 2

Point Two is 20% to 1 and 80% to 2

Point Three is ???

Point Four is ???

Point Five is ???

Point Six is 0% to 4 and 100% to 5

I'm trying to find what the percentage is in relation to the the points on the other chain.

A: 1................2...............3...............4................5

\ / \ / \ / \ /

B: 1...........2...|.......3.......|......4........|....5..........6[/QUOTE]

So LineB Point One is 100% to 1 and 0% to 2

Point Two is 20% to 1 and 80% to 2

Point Three is ???

Point Four is ???

Point Five is ???

Point Six is 0% to 4 and 100% to 5

- Joined
- Nov 12, 2017

- Messages
- 3,061

Is my correction above (putting the picture into CODE form) what you intended?More like this.

I'm trying to find what the percentage is in relation to the the points on the other chain.

So LineB Point One is 100% to 1 and 0% to 2Code:`[FONT=courier new]A: 1................2...............3...............4................5 \ / \ / \ / \ / B: 1............2...|.......3.......|......4........|....5...........6[/FONT]`

Point Two is 20% to 1 and 80% to 2

Point Three is ???

Point Four is ???

Point Five is ???

Point Six is 0% to 4 and 100% to 5

I'm not quite sure of your terminology. How is point 2 of line B "20% to 1"? My understanding of what you wanted was "80% of the way

What's happening is that each point in B falls 20% behind the previous one: point B3 is

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