calculus help

lpaynerdh

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Feb 6, 2015
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We are working on limits in class and I am stuck on one problem. I am not really sure why I can't figure this one out. Any help will be very appreciated. Thanks in advance. lim (cos (2theta) tan (2theta))/theta x approaches 0
 
An obvious point is that \(\displaystyle tan(2\theta)= \frac{sin(2\theta)}{cos(2\theta)}\) so that \(\displaystyle \frac{cos(2\theta)tan(2\theta)}{\theta}= \frac{cos(2\theta)\frac{sin(2\theta)}{cos(2\theta)}}{\theta}\)\(\displaystyle = \frac{sin(2\theta)}{\theta}\)

Now, multiply both numerator and denominator by 2:
\(\displaystyle 2\frac{sin(2\theta)}{2\theta}\).

Can you finish that?
 
We are working on limits in class and I am stuck on one problem. I am not really sure why I can't figure this one out. Any help will be very appreciated. Thanks in advance. lim (cos (2theta) tan (2theta))/theta x approaches 0
Let trig(x) be any trig function of x. Then almost always if you have lim as x->0 of trig(x)/x or lim as x->0 of x/trig(x) you want to get sinx/x or x/sinx and both of these two fractions go to 1 as x goes to 0. Can you prove that!
 
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