Calculus: Pressure on a wall (If the pressure at the center of a volume is given, then the pressure on the wall...)

I'mLearning

New member
Joined
Jan 22, 2024
Messages
8
I'm reading abouot the pressure gradient force.

If the pressure at the center of a volume is given, then the pressure on the wall of the volume may be expressed in a Taylor series expansion:
[math]p_{0}+\frac{\partial\,p}{\partial\,x}\frac{\delta\,x}{2}+higher-order terms[/math].

[math]\delta\,x[/math] is the volume width and [math]p_{0}[/math] is the pressure at the center.

I'd like to understand without getting lost in the maths. What is the essential idea:
 
Last edited:
Without seeing more context what you posted looks like the standard approximation using derivatives. I.e., if the pressure is a function of [imath]x[/imath], then you can write [imath]p(x_0 + \delta x) \approx p(x_0) + \frac{\partial p}{\partial x} \delta x[/imath].

BTW, the use of partial derivatives implies that the pressure depends on some other variables too.
 
Top