D is just the discriminant. So i was thinking something like. D=b^2-4ac. Where the discriminant I Got to 0. This means 1 root, whereas the formula used is -b/2a. Where i get 2/2=1. I am just in doubt about if (c1+c2t)e^t is correct?
Suppose \((x,y)=(1,-1)\). This would violate \(x+y>0\), but would it cause division by zero? There is only one ordered pair \((x,y)\in\mathbb{R}\) that can cause division by zero. What would that be?
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