In case you're not provided with the fully-worked solution, please reply showing what you've tried and how far you've gotten.
You drew the right triangle in the appropriate quadrant ("o[sic] < a < pi/2") with "a" labelling the angle, you labelled the "opposite" and "adjacent" sides according to the given equivalence ("tan(a) = 2/1"), you applied the Pythagorean Theorem to find the length of the hypotenuse, and... then what?
Thank you.
Eliz.