Can a circle be considered a Function?
- Thread starter mel_001
- Start date
If a quantity y depends on a quantity x in a way that each value of x determines one value of y, then "y is a function of x".
So, take \(\displaystyle f(x)=\pm\sqrt{x^{2}-9}\)
This is a circle of radius 3 centered at the origin. Its domain is [-3,3].
It's range is [0,3].
Another way to look at it would be that a circles area is dependent on its radius, so it's a function of r.
So, take \(\displaystyle f(x)=\pm\sqrt{x^{2}-9}\)
This is a circle of radius 3 centered at the origin. Its domain is [-3,3].
It's range is [0,3].
Another way to look at it would be that a circles area is dependent on its radius, so it's a function of r.
stapel said:
I've been trying to identify if circle can be considered as a function, using the Vertical line test where it is said that a set of points in a coordinate plane is the graph of a function if and only if no vertical line intersects the graph at more than one point.