can any one help with this problem?

[goldgold]

Log[x^2, x/8]^(1/2) Log[2, x] + 3 >= 0
this is the best way i can write the problem, soultian with steps please

 

[goldgold]

in the future do us a favor and rotate your pic before posting it please.

It's an odd function so I want to verify it's correct

\(\displaystyle \sqrt{log_{x^2}(\frac{x}{8}})\cdot log_2(x)+3\geq0\)

it would make much more sense if the log in the square root was just \(\displaystyle log_2(\frac{x}{8})\)

no its just as i wrote it.

i got the the 2 soultion x>=8 and x<1 but there is another one x>=1/8 that i just cant get

 

[goldgold]

thx

 

[goldgold]

lol im still stuck, can you go on with the steps?

 

[goldgold]

i think im in dumb mod i just cant get to 1/8<=x<1

 

[stapel]

i think im in dumb mod i just cant get to 1/8<=x<1

Please reply showing your steps, so we can try to figure out where things are going wrong. Thank you!

 

[goldgold]

i got to the part where i replace u with logx but i just cant go on from that point, it just gives me one x every time

 

[goldgold]

so now can you help me find the boundaries of x