G Guest Guest Oct 19, 2005 #1 Find the equation of the line tangent to the graph y=2x^2-3x+1 at the point where x=2. Write your answer in slope intercept form: y=mx+k.
Find the equation of the line tangent to the graph y=2x^2-3x+1 at the point where x=2. Write your answer in slope intercept form: y=mx+k.
G Gene Senior Member Joined Oct 8, 2003 Messages 1,904 Oct 19, 2005 #2 It is best if you show your work so we know where to help. y=2x^2-3x+1 Find dy/dx y'=4x-3 Solve at x=2 y(2)=3 Solve at x=2 y'(2)=5 = m y=mx+k 3=5*2+k=10+k k=-7
It is best if you show your work so we know where to help. y=2x^2-3x+1 Find dy/dx y'=4x-3 Solve at x=2 y(2)=3 Solve at x=2 y'(2)=5 = m y=mx+k 3=5*2+k=10+k k=-7
