J JWS New member Joined Sep 12, 2011 Messages 4 Sep 15, 2011 #1 My equation is: h(x) = 2x^2 -7x +5 h(-1/5) I have worked it out to what I believe the answer is: h(-1/5) = 210/25 I will be happy to show my work but did not want to clutter space if my answer is correct Thanks...
My equation is: h(x) = 2x^2 -7x +5 h(-1/5) I have worked it out to what I believe the answer is: h(-1/5) = 210/25 I will be happy to show my work but did not want to clutter space if my answer is correct Thanks...
S Someone2841 New member Joined Sep 7, 2011 Messages 35 Sep 15, 2011 #2 JWS said: My equation is: h(x) = 2x^2 -7x +5 h(-1/5) I have worked it out to what I believe the answer is: h(-1/5) = 210/25 I will be happy to show my work but did not want to clutter space if my answer is correct Thanks... Click to expand... \(\displaystyle h(\frac{-1}{5}) = 2(\frac{-1}{5})^{2} -7(\frac{-1}{5}) +5 = \frac{2}{25} + \frac{7}{5} + 5 = \frac{2}{25} + \frac{35}{25} + \frac{125}{25} = \frac{162}{25}\) Last edited by a moderator: Sep 15, 2011
JWS said: My equation is: h(x) = 2x^2 -7x +5 h(-1/5) I have worked it out to what I believe the answer is: h(-1/5) = 210/25 I will be happy to show my work but did not want to clutter space if my answer is correct Thanks... Click to expand... \(\displaystyle h(\frac{-1}{5}) = 2(\frac{-1}{5})^{2} -7(\frac{-1}{5}) +5 = \frac{2}{25} + \frac{7}{5} + 5 = \frac{2}{25} + \frac{35}{25} + \frac{125}{25} = \frac{162}{25}\)
