Can someone help me?

[Raehya]

Find the equation of the line through the point (1,3) and the point of intersection of the lines 2x+y+1=0 and 2x-5y+7=0

 

[Deleted member 4993]

Find the equation of the line through the point (1,3) and the point of intersection of the lines 2x+y+1=0 and 2x-5y+7=0

What would be the coordinate of the point of intersection of the given two lines:

2x + y + 1 = 0 and

2x - 5y + 7 = 0

 

[blamocur]

Find the equation of the line through the point (1,3) and the point of intersection of the lines 2x+y+1=0 and 2x-5y+7=0

Someone used a pretty neat technique in an earlier post (don't remember which one) : if [imath]f(x,y)=0[/imath] and [imath]g(x,y)=0[/imath] are equations of straight lines then the equation of any straight line containing their intersection point can be expressed as [imath]\alpha f(x,y) + \beta g(x,y) = 0[/imath] for some values of [imath]\alpha[/imath] and [imath]\beta[/imath]....edited

 

[Deleted member 4993]

Someone used a pretty neat technique in an earlier post (don't remember which one) : if [imath]f(x)=0[/imath] and [imath]g(x)=0[/imath] are equations of straight lines then the equation of any straight line containing their intersection point can be expressed as [imath]\alpha f(x) + \beta g(x) = 0[/imath] for some values of [imath]\alpha[/imath] and [imath]\beta[/imath]..

Did you mean:

if f(x,y)=0 and

g(x,y)=0 are equations of straight lines then.................

 

[blamocur]

Did you mean:

if f(x,y)=0 and

g(x,y)=0 are equations of straight lines then.................

I did, kind of. But I was kind of sloppy and used 'x' to denote a vector.