Can someone tell if this is right?

[think_bot]

is this just webassign being webassign?

 

[think_bot]

what does it look like? I saw it as (7u)^1/2 + (10u)^1/2

 

[JeffM]

View attachment 3520is this just webassign being webassign?

As romesk said

\(\displaystyle g(u) = \sqrt{7}u + \sqrt{10u} = \sqrt{7}u + \sqrt{10}u^{(1/2)} \implies g'(u) = \sqrt{7} + \sqrt{10} * \dfrac{1}{2} * u^{-(1/2)} = \sqrt{7} + \dfrac{\sqrt{10}}{2\sqrt{u}}.\)

However,

\(\displaystyle g(u) = \sqrt{7u} + \sqrt{10u} = \sqrt{7}\sqrt{u} + \sqrt{10}\sqrt{u} =u^{(1/2)}\left(\sqrt{7} + \sqrt{10}\right) \implies g'(u) = \dfrac{1}{2} * u^{-(1/2)} * \left(\sqrt{7} + \sqrt{10}\right) = \dfrac{\sqrt{7} + \sqrt{10}}{2\sqrt{u}}.\)

What was the problem? What did you put into the software?

 

[JeffM]

what does it look like? I saw it as (7u)^1/2 + (10u)^1/2

Umh. How do we know which it is? it's your question.

 

[richardt]

In the first term, the vinculum extends over the 7 only. Thus the given expression becomes, 7^1/2 u + 10^1/2u^1/2, making the derivative of the first term 7^1/2.

Rich

 

[think_bot]

Thanks Everyone for the quick responses