Can someone tell me how this is simplified: -9/(3x^2)^3 = -1/3x^6

[Kaanha]

Can someone explain to me how this is simplified

-9/(3x^2)^3 = -1/3x^6

 

[Deleted member 4993]

Can someone explain to me how this is simplified

-9/(3x^2)^3 = -1/3x^6

First simplify (3x^2)^3 = ?

 

[JeffM]

It does not appear that you read this thread as you should have.

https://www.freemathhelp.com/forum/threads/112086-Guidelines-Summary?p=436773#post436773

I usually try to lead someone through a thought process, but this time the process is so trivial that it is not worth doing so.

\(\displaystyle \dfrac{-\ 9}{(3x^2)^3} = \dfrac{-\ (3)(3)}{(3)(3)(3)(x * x)(x * x)(x * x)} = \dfrac{-\ 1}{3x^6}.\)

 

[pka]

Can someone explain to me how this is simplified
-9/(3x^2)^3 = -1/3x^6

Surely all can see that:
\(\displaystyle \dfrac{-9}{(3x^2)^3}=\dfrac{-3^2}{3^3x^6}=\dfrac{-1}{3x^6}\)

 

[lookagain]

-9/(3x^2)^3 = -1/3x^6

You need grouping symbols around that second denominator:

-1/(3x^6)