Can we writing any real number in the from of xPn? Is it possible?

[Nagendra]

Calculate x and n, C can be any real numbers in below equation


$x∙(x-1)∙(x-2)….…..(x-n)=C$

 

[Steven G]

I think that you should have read the posting guidelines before posting. Please read the guidelines and then make an appropriate post.

 

[Steven G]

x=C and n=0 works.

 

[Dr.Peterson]

Calculate x and n, C can be any real numbers in below equation


$x∙(x-1)∙(x-2)….…..(x-n)=C$

The equation doesn't make any sense if x and n can be any real numbers. Shouldn't at least n be restricted to non-negative integers? And if you intend the LHS to be xPn, that would normally require both x and n to be non-negative integers (and therefore C also).

Where does this problem come from? Does the context involve some sort of extension of these concepts to non-integers?