Can you explain this?

[Mathmasteriw]

Hi Guys and gals,
can anyone explain what the 2 & 0 on top and bottom of the square brakets do in relation to inside the brakets?
For example the answer i get for inside brakets are = 0.37 but what effect do these numbers have on this answer?
Any help appreciated!

 

[Harry_the_cat]

Is this part of an integration problem?

 

[Mathmasteriw]

Is this part of an integration problem?

Yes it's part of a intergation problem

 

[Harry_the_cat]

They would have been the boundaries of the definite integral.
What do you mean by "the answer i get for inside brakets are = 0.37"? How did you calculate that?

 

[Mathmasteriw]

so t=1 and RC =1 so the answer i get to the equation inside the bracket is 0.37, so what dose the 2 and the 0 do to the 0.37?
or is it correct as 0.37?

 

[Harry_the_cat]

I'm assuming t is the variable?? Can you please post the original question?

 

[Harry_the_cat]

How did you get that t=1?

 

[Mathmasteriw]

 

[Mathmasteriw]

I know in the original photo there is a 2 and a 0 but for my question i would use 1 and 0

 

[Harry_the_cat]

So where does the 0 and the 2 come into the question? Where did you see the statement you originally poated?

 

[Harry_the_cat]

I know in the original photo there is a 2 and a 0 but for my question i would use 1 and 0

Oh ok then. Now it's a bit clearer.
How did you get 0.37?

 

[Harry_the_cat]

e^-(1/1) =0.37 Is that how?

 

[Harry_the_cat]

 

[Steven G]

Yes it's part of a intergation problem

Were does numbers originally the limits of integration? As the 2 and 3 are in [math]\int_2^3f(t)dt?[/math]

 

[Dr.Peterson]

Hi Guys and gals,
can anyone explain what the 2 & 0 on top and bottom of the square brakets do in relation to inside the brakets?
For example the answer i get for inside brakets are = 0.37 but what effect do these numbers have on this answer?
Any help appreciated!
View attachment 24387

The notation you're asking about means "evaluate the difference in the expression when t changes from 0 to 2"; that is, \([f(t)]_a^b\) means \(f(b) - f(a)\).

This should be explained in your textbook; if not, see "Example (continued)" in https://www.mathsisfun.com/calculus/integration-definite.html, or the statement of the theorem in https://tutorial.math.lamar.edu/classes/calci/computingdefiniteintegrals.aspx

 

[duffymercy]

2 and 0 stands for time passed after switch got closed. In the other words, you are trying to find how many charge stored in 2 seconds. Maybe it makes no sense to you beacause when t = 0, charge is 0. But you will see more complicated circuits which have 2 different equations for current and voltage. For example;


You will get better when you see step responses.

 

[Mathmasteriw]

The notation you're asking about means "evaluate the difference in the expression when t changes from 0 to 2"; that is, \([f(t)]_a^b\) means \(f(b) - f(a)\).

This should be explained in your textbook; if not, see "Example (continued)" in https://www.mathsisfun.com/calculus/integration-definite.html, or the statement of the theorem in https://tutorial.math.lamar.edu/classes/calci/computingdefiniteintegrals.aspx

Thanks for that, it explains much better in here than my workbook!
Thanks Doc!