J jsantos New member Joined Feb 28, 2006 Messages 1 Feb 28, 2006 #1 find center-radius form of equation of circle with center (-2,-3) and tangent to the x-axis (x+2)^2+(y+3)^2=r^2 i do not know how to find r^2 i was provided the answer (x+2)^2 + (y+3)^2=9 how do i come up with nine from r
find center-radius form of equation of circle with center (-2,-3) and tangent to the x-axis (x+2)^2+(y+3)^2=r^2 i do not know how to find r^2 i was provided the answer (x+2)^2 + (y+3)^2=9 how do i come up with nine from r
pka Elite Member Joined Jan 29, 2005 Messages 11,978 Feb 28, 2006 #2 How far is the center, (−2, −3), from the x-axis? That is your radius.
