Circle Theorem Problem

Toby.tc

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Please can someone help me solve this using no more than GCSE level circle theorems?
 

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I don’t understand where to begin, I tried to draw in some radii from a centre O but I got no where. I need to solve for m and n.
First label all the vertices. Show us the labeled sketch. Think about the exterior/interior angles of triangles also.
 
First label all the vertices. Show us the labeled sketch. Think about the exterior/interior angles of triangles also.
I did it. Just needed a bit of thinking. Here’s the proof with enhanced diagram of added letters:
 

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Please can someone help me solve this using no more than GCSE level circle theorems?
@Toby, You should have followed S.Kann's suggestion to label the vertices.
So start and label the vertices on the circle: \(m(\angle A)=15^o\).
Now going clockwise \(B,~C,~D\). Then \(m(\angle E)=20^o~\&~m(\angle F)=u^o\).
By the inscribed angle theorem we know \(m(\widehat{CD})=30^o\).
We also know that \(20^o=\frac{1}{2}\left(m(\widehat{AB})-m(\widehat{CD})\right)\). Which gives \(m(\widehat{AB})\).
Now can you continue?
 
@Toby, You should have followed S.Kann's suggestion to label the vertices.
So start and label the vertices on the circle: \(m(\angle A)=15^o\).
Now going clockwise \(B,~C,~D\). Then \(m(\angle E)=20^o~\&~m(\angle F)=u^o\).
By the inscribed angle theorem we know \(m(\widehat{CD})=30^o\).
We also know that \(20^o=\frac{1}{2}\left(m(\widehat{AB})-m(\widehat{CD})\right)\). Which gives \(m(\widehat{AB})\).
Now can you continue?
I’ve already completed the solution, but I can’t see how inscribed circle theorem is applicable as vertices E is not on the circumference. (Unless you are referring to an alternate perspective I haven’t seen). Thanks for the prompts, I’ll make sure to label my vertices next time.
 
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