greatwhiteshark
Full Member
- Joined
- May 8, 2005
- Messages
- 279
NOTE: A = alpha, B = beta Y = gamma
Show that sinA/a = SinB/b = SinY/c = 1/2r where r = the radius of the circle circumscribing triangle ABC whose sides are a, b and c.
HINT: Draw the diameter AB'. Then B = angle ABC = angle AB'C and angle ACB' = 90 degrees.
Show that sinA/a = SinB/b = SinY/c = 1/2r where r = the radius of the circle circumscribing triangle ABC whose sides are a, b and c.
HINT: Draw the diameter AB'. Then B = angle ABC = angle AB'C and angle ACB' = 90 degrees.